Track / Stage 3 / 219 of 260 #219 of 2000

Problem 219

AMC 10/12, early questions

Algebra Difficulty 3.8 Find the answer Državno tekmovanje v znanju matematike za dijake srednjih tehniških in strokovnih šol · Slovenia

Problem:

Naj za realni števili $x$ in $y$ velja $\frac{x}{x+y}=101$ . Kolikšna je vrednost izraza $\frac{y-x}{y}$ ?

(A) 1,02
(B) 100
(C) 201
(D) 2,01
(E) 1,01

Your answer

Official solution

Solution:

Enakost pomnožimo z imenovalcem in izrazimo $x=-1,01 y$ , to vstavimo v izraz $\frac{y-x}{y}=$ $\frac{y+1,01 y}{y}=\frac{2,01 y}{y}=2,01$ .

Source: MathNet, licensed CC-BY-4.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.