GeometryDifficulty 8.5Prove it62nd NMO SELECTION TESTS FOR THE BALKAN AND INTERNATIONAL MATHEMATICAL OLYMPIADS · Romania
Let A0A1A2 be a non-equilateral triangle. The incircle of the triangle A0A1A2 touches the side AiAi+1 at the point Ti+2 (indices are reduced modulo 3). Let Xi be the perpendicular foot dropped from the point Ti onto the line Ti+1Ti+2. Show that the lines AiXi are concurrent at a point situated on the Euler line of the triangle T0T1T2.
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Official solution
The lines AiAi+1 and XiXi+1 are parallel, for they are both antiparallel to the line TiTi+1. Hence the triangles A0A1A2 and X0X1X2 are homologous: the three lines AiXi are concurrent at the homology centre which lies on the homology line. The latter passes through the incentres of the two triangles: one is the circumcentre of the triangle T0T1T2 and the other the orthocentre. The conclusion follows.
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