Olympiad Maths Prep

Track / Stage 3 / 194 of 260 #194 of 2000

Problem 194

AMC 10/12, early questions
Geometry Difficulty 3.7 Find the answer 16. tekmovanje v znanju matematike za dijake srednjih tehniških in strokovnih šol Državno tekmovanje · Slovenia

Problem:

Kocko z robom dolžine aa razrežemo na 8 malih skladnih kock. Površino ene take male kocke označimo s PP. Koliko je PP?

(A) a22\frac{a^{2}}{2}
(B) 3a24\frac{3 a^{2}}{4}
(C) a28\frac{a^{2}}{8}
(D) 3a22\frac{3 a^{2}}{2}
(E) a8a^{8}

Official solution

Solution:

Označimo z a1a_{1} dolžino roba male kocke. Upoštevamo, da je prostornina male kocke a13=a38a_{1}^{3} = \frac{a^{3}}{8} in dobimo a1=a2a_{1} = \frac{a}{2}. Torej velja P=6a12=6(a2)2=3a22P = 6 a_{1}^{2} = 6\left(\frac{a}{2}\right)^{2} = \frac{3 a^{2}}{2}.

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