Do there exist two natural numbers x and y, having the same number of natural divisors, such that x<y, and the sum of all divisors of x (including 1 and the number itself) is greater than the sum of natural divisors of y (including 1 and the number itself)?
Official solution
Answer: Yes
Solution:
For example, the numbers 38 and 39:1+2+19+38=60>56=1+3+13+39.
Source: NuminaMath-1.5,
licensed Apache-2.0.
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