Olympiad Maths Prep

Track / Stage 4 / 151 of 340 #411 of 2000

Problem 411

AMC 12 late, AIME early
Number theory Difficulty 4.8 Find the answer

2. (8 points) Xiaoming's family keeps three hens, the first hen lays one egg per day, the second hen lays one egg every two days, and the third hen lays one egg every three days. It is known that on January 1st, all three hens laid eggs, so in the thirty-one days of January, these three hens laid \qquad eggs in total,

Official solution

【Answer】Solution: The first one laid 31 eggs, the second one laid 16 eggs, and the third one laid 11 eggs. 31+16+11=5831+16+11=58 (eggs)

Answer: These three hens laid a total of 58 eggs.
Therefore, the answer is: 58.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.