Olympiad Maths Prep

Track / Stage 4 / 49 of 340 #309 of 2000

Problem 309

AMC 12 late, AIME early
Geometry Difficulty 4.5 Find the answer

3. For an equilateral ABC\triangle ABC with side length 11, PP is a point on side ABAB. PQBC,QRAC,RSABPQ \perp BC, \quad QR \perp AC, \quad RS \perp AB (where Q,R,SQ, R, S are the feet of the perpendiculars). If SP=14SP=\frac{1}{4}, then AP=AP=

Official solution

3. 19\frac{1}{9} or 59\frac{5}{9},

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