Olympiad Maths Prep

Track / Stage 5 / 54 of 400 #654 of 2000

Problem 654

AIME late
Combinatorics Difficulty 5.2 Find the answer

21.1.3 { }^{\star \star} Divide each side of the equilateral ABC\triangle A B C into nn equal parts, and draw lines parallel to the sides through the division points. Find the number of parallelograms in the resulting figure.

Official solution

Consider the number of parallelograms without any side parallel to BCBC. Each such parallelogram corresponds one-to-one with four different points on BCB^{\prime} C^{\prime} (as shown in the figure), so there are Cn+24\mathrm{C}_{n+2}^{4} parallelograms. Similarly, the number of parallelograms without any side parallel to ACAC or ABAB is also Cn+24\mathrm{C}_{n+2}^{4} each. Therefore, there are a total of 3Cn+243 \cdot \mathrm{C}_{n+2}^{4} parallelograms.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.