Olympiad Maths Prep

Track / Stage 4 / 299 of 340 #559 of 2000

Problem 559

AMC 12 late, AIME early
Algebra Difficulty 5.0 Find the answer

2. Determine the fourth and fifth terms of the sequence 83,49,227,\frac{8}{3}, \frac{4}{9}, \frac{2}{27}, \ldots.

Official solution

2. The next term of the sequence is obtained by dividing the numerator of the previous term by 2 and multiplying the denominator by 3.

2 POINTS

The fourth term of the sequence is 2:2273=181\frac{2: 2}{27 \cdot 3}=\frac{1}{81}.

2 POINTS

The fifth term of the sequence is 1:2813=12243=1486\frac{1: 2}{81 \cdot 3}=\frac{\frac{1}{2}}{243}=\frac{1}{486}

2 POINTS

TOTAL 6 POINTS

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