Olympiad Maths Prep

Track / Stage 4 / 78 of 340 #338 of 2000

Problem 338

AMC 12 late, AIME early
Algebra Difficulty 4.7 Find the answer

2 Given the function y=f(x)y=f(x) has an inverse function y=f1(x)y=f^{-1}(x), the graph of y=f(x)y=f(x) is rotated counterclockwise by 9090^{\circ} around (1,1)(1,-1), the equation of the resulting curve is ( ).
(A) y=f1(x)2y=f^{-1}(-x)-2
(B) y=f1(x)2y=-f^{-1}(-x)-2
(C) y=f1(x+1)1y=f^{-1}(-x+1)-1
(D) y=f1(x1)+1y=f^{-1}(-x-1)+1

Official solution

(2) A Hint: The point (t,f(t))(t, f(t)) rotates 9090^{\circ} around (1,1)(1,-1), resulting in (f(t),t(-f(t), t-
2). Let x=f(t)x=-f(t), then t=f1(x)t=f^{-1}(-x), thus
y=t2=f1(x)2. y=t-2=f^{-1}(-x)-2 .

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.