Let be a parallelogram with Let be the point on the line such that and let be the point on the line such that . The circumcircle of the triangle intersects the line again in and the line again in . Let be the reflection of over the line and the reflection of over the line . Prove that lie on the same line.
Problem 1673
Official solution
1. Identify the given elements and their properties:
- is a parallelogram with .
- is a point on the line such that .
- is a point on the line such that .
- The circumcircle of intersects the line again at and the line again at .
- is the reflection of over the line .
- is the reflection of over the line .
2. **Prove that and are isosceles trapezoids:**
- Since and , triangles and are isosceles.
- In , since , .
- In , since , .
- Since lies on the circumcircle of and intersects again, .
- Similarly, since lies on the circumcircle of and intersects again, .
3. **Show that the circumcircles of and meet at and another point :**
- Let the circumcircles of and intersect at and another point .
- Since is an isosceles trapezoid, .
- Since is an isosceles trapezoid, .
- Therefore, .
4. **Prove that and are collinear:**
- Since , must be collinear.
- Similarly, since , must be collinear.
5. **Determine the positions of and :**
- Let the perpendicular from to intersect at .
- Since and , .
- Similarly, let the perpendicular from to intersect at .
- Since and , .
6. **Conclude that lie on the same line:**
- Since and are reflections of and over and respectively, and both lie on , are collinear.