Olympiad Maths Prep

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Problem 717

AIME late
Algebra Difficulty 5.3 Find the answer

## Task A-1.2.

Tea mixed a dough from three ingredients: flour, water, and eggs. The mass of flour in the dough to the mass of water is in the ratio of 7:27: 2, while the mass of water to the mass of eggs is in the ratio of 5 : 2. The total mass of the dough is 1470 grams. Determine the mass of each ingredient.

Official solution

## First solution.

Let's denote the masses of flour, water, and eggs by x,yx, y, and zz, respectively.

The given ratios can be represented as x:y=7:2=35:10x: y=7: 2=35: 10 and y:z=5:2=10:4y: z=5: 2=10: 4, i.e., as the ratio

x:y:z=35:10:4 x: y: z=35: 10: 4

1 point

Therefore, we can write x=35t,y=10t and z=4tx=35 t, y=10 t \text{ and } z=4 t, where tt is a positive real number. 1 point

The total mass is 1470 grams, i.e., 35t+10t+4t=147035 t + 10 t + 4 t = 1470. 1 point

Thus, we have 49t=147049 t = 1470, i.e., t=30t = 30.

The total mass of flour is 35t=1050 g35 t = 1050 \text{ g}, water 10t=300 g10 t = 300 \text{ g}, and eggs 4t=120 g4 t = 120 \text{ g}.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.