10. Given positive integers x1,x2,x3,⋯,x2020 satisfy x1+x2+x3+⋯+x2020=x1x2x3⋯x2020. Then among these 2020 positive integers, the maximum number of values that can be 1 is .
Official solution
2018
Source: NuminaMath-1.5,
licensed Apache-2.0.
Statement and solution reproduced as published; topic, difficulty and ordering added
by this site.