Olympiad Maths Prep

Track / Stage 3 / 59 of 260 #59 of 2000

Problem 59

AMC 10/12, early questions
Geometry Difficulty 3.2 Find the answer

Given a sector with a radius of 22 and an arc length of 8π3\frac{8\pi}{3}, the central angle α\alpha satisfies sinα=\sin \alpha=____.

Official solution

Analysis

This question examines the method of calculating the radian measure of the central angle of a sector and the value of a trigonometric function, focusing on computational ability. By directly using the formula relating arc length, radius, and central angle, we can find the radian measure of the sector's central angle, and then determine the value of the trigonometric function for a special angle.

Solution

Given that the radius is 22 and the arc length is 8π3\frac{8\pi}{3}, the central angle of the sector α\alpha can be calculated as α=8π32=4π3\alpha= \frac{ \frac{8\pi}{3}}{2}= \frac{4\pi}{3}.

Therefore, sin4π3=sinπ3=32\sin \frac{4\pi}{3}=-\sin \frac{\pi}{3}=- \frac{ \sqrt{3}}{2}.

Hence, the answer is 32\boxed{- \frac{ \sqrt{3}}{2}}.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.