Olympiad Maths Prep

Track / Stage 4 / 46 of 340 #306 of 2000

Problem 306

AMC 12 late, AIME early
Algebra Difficulty 4.6 Find the answer

17. logx5+logx(5x)2.25=(logx5)2\log _{x} \sqrt{5}+\log _{x}(5 x)-2.25=\left(\log _{x} \sqrt{5}\right)^{2}.

Official solution

17. Simple transformations lead to the equation

logx256logx5+5=0\log _{x}^{2} 5-6 \log _{x} 5+5=0. From which x1=55,x2=5x_{1}=\sqrt[5]{5}, x_{2}=5.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.