Olympiad Maths Prep

Track / Stage 3 / 24 of 260 #24 of 2000

Problem 24

AMC 10/12, early questions
Number theory Difficulty 3.1 Find the answer

Two different prime numbers between 44 and 1818 are chosen. When their sum is subtracted from their product, which of the following numbers could be obtained?
(A) 22(B) 60(C) 119(D) 180(E) 231\textbf{(A)}\ 22 \qquad\textbf{(B)}\ 60 \qquad\textbf{(C)}\ 119 \qquad\textbf{(D)}\ 180 \qquad\textbf{(E)}\ 231

Official solution

Any two prime numbers between 4 and 18 have an odd product and an even sum. Any odd number minus an even number is an odd number, so we can eliminate A, B, and D. Since the highest two prime numbers we can pick are 13 and 17, the highest number we can make is (13)(17)(13+17)=22130=191(13)(17)-(13+17) = 221 - 30 = 191. Thus, we can eliminate E. So, the answer must be (C) 119\boxed{\textbf{(C) }119}.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.