Olympiad Maths Prep

Track / Stage 4 / 220 of 340 #480 of 2000

Problem 480

AMC 12 late, AIME early
Combinatorics Difficulty 4.9 Find the answer

3. Cut a 3×33 \times 3 square without the central cell into 5 pieces that can be assembled into a square?

#

This one wants a proof. Work it on paper, read the official solution, then mark yourself honestly — the ladder only means something if the record is true.

Official solution

# Solution:

The solution is shown in the figure. On the left fragment - the cutting. On the right - the assembly scheme of the new square.

## Instructions for checking:

!

If the solution is done on a grid, no justification for the correctness of the cutting and assembly is required.

If the scheme is not on a grid, errors are very likely. Be attentive!

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.