Olympiad Maths Prep

Track / Stage 4 / 323 of 340 #583 of 2000

Problem 583

AMC 12 late, AIME early
Algebra Difficulty 5.0 Find the answer

A1. Maja filled two identical pitchers with lemonade, so that the first pitcher was filled to 13\frac{1}{3}, and the second to 25\frac{2}{5}. Then she added water to both pitchers until they were full. Finally, she poured the contents of both pitchers into a larger bowl, without any liquid spilling over the edge of the bowl. What fraction of the liquid in the bowl is lemonade?
(A) 18\frac{1}{8}
(B) 316\frac{3}{16}
(C) 1130\frac{11}{30}
(D) 1119\frac{11}{19}
(E) 1115\frac{11}{15}

Official solution

A1. Let the amount of liquid that one basket can hold be denoted by ee. Then, in the jug, there is 13e+25e=1115e\frac{1}{3} e + \frac{2}{5} e = \frac{11}{15} e of lemonade out of a total of 2e2 e liquid. Therefore, the lemonade represents 1115e2e=1130\frac{\frac{11}{15} e}{2 e} = \frac{11}{30} of the liquid in the jug.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.