Olympiad Maths Prep

Track / Stage 3 / 13 of 260 #13 of 2000

Problem 13

AMC 10/12, early questions
Combinatorics Difficulty 3.0 Find the answer

Jamal wants to save 30 files onto disks, each with 1.44 MB space. 3 of the files take up 0.8 MB, 12 of the files take up 0.7 MB, and the rest take up 0.4 MB. It is not possible to split a file onto 2 different disks. What is the smallest number of disks needed to store all 30 files?
(A) 12(B) 13(C) 14(D) 15(E)16\textbf{(A)}\ 12 \qquad \textbf{(B)}\ 13 \qquad \textbf{(C)}\ 14 \qquad \textbf{(D)}\ 15 \qquad \textbf{(E)} 16

Official solution

A 0.80.8 MB file can either be on its own disk, or share it with a 0.40.4 MB. Clearly it is better to pick the second possibility. Thus we will have 33 disks, each with one 0.80.8 MB file and one 0.40.4 MB file.
We are left with 1212 files of 0.70.7 MB each, and 1212 files of 0.40.4 MB each. Their total size is 12(0.7+0.4)=13.212\cdot (0.7 + 0.4) = 13.2 MB. The total capacity of 99 disks is 91.44=12.969\cdot 1.44 = 12.96 MB, hence we need at least 1010 more disks. And we can easily verify that 1010 disks are indeed enough: six of them will carry two 0.70.7 MB files each, and four will carry three 0.40.4 MB files each.
Thus our answer is 3+10=(B) 133+10 = \boxed{\textbf{(B) }13 }.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.