Olympiad Maths Prep

Track / Stage 4 / 141 of 340 #401 of 2000

Problem 401

AMC 12 late, AIME early
Geometry Difficulty 4.7 Find the answer

2. Given PP is the center of the upper base A1B1C1\triangle A_{1} B_{1} C_{1} of a regular triangular prism ABCA1B1C1A B C-A_{1} B_{1} C_{1}, construct a plane BCDAPB C D \perp A P, intersecting the edge AA1A A_{1} at point DD. If AA1=2AB=2A A_{1}=2 A B=2, then the volume of the tetrahedron DABCD-A B C is ( ).
(A) 348\frac{\sqrt{3}}{48}
(B) 324\frac{\sqrt{3}}{24}
(C) 316\frac{\sqrt{3}}{16}
(D) 312\frac{\sqrt{3}}{12}

Official solution

2. A.

As shown in Figure 3, let the plane AA1PA A_{1} P intersect the edges BCB C and B1C1B_{1} C_{1} at points EE and E1E_{1}, respectively.
In the rectangle AEE1A1A E E_{1} A_{1}, AA1=2A A_{1}=2,
AE=A1E1=32A E=A_{1} E_{1}=\frac{\sqrt{3}}{2},
A1P=33 A_{1} P=\frac{\sqrt{3}}{3} \text {. }

From AA1AE=APED\frac{A A_{1}}{A E}=\frac{A P}{E D}, we get

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.