Olympiad Maths Prep

Track / Stage 4 / 41 of 340 #301 of 2000

Problem 301

AMC 12 late, AIME early
Geometry Difficulty 4.5 Find the answer

Six. (15 points) Given points DD, EE, and FF are on the sides BCBC, CACA, and ABAB of ABC\triangle ABC respectively, GG is the intersection of BEBE and CFCF, and BD=DC=CA=AFBD=DC=CA=AF, AE=AE= EC=BFEC=BF. Then, the value of DGBC\frac{DG}{BC} is \qquad

Official solution

Six、 18\frac{1}{8}

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.