Olympiad Maths Prep

Track / Stage 4 / 263 of 340 #523 of 2000

Problem 523

AMC 12 late, AIME early
Algebra Difficulty 4.9 Find the answer

6. Let positive integers m,nm, n satisfy m<nm<n, and
1m2+m+1(m+1)2+(m+1)++1n2+n=123 \frac{1}{m^{2}+m}+\frac{1}{(m+1)^{2}+(m+1)}+\cdots+\frac{1}{n^{2}+n}=\frac{1}{23} \text {. }

Then the value of m+nm+n is \qquad .

Official solution

6.5276.527

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.