A circle intersects the coordinate axes at points A(a,0),B(b,0)C(0,c) and D(0,d). Find the coordinates of its center.
Official solution
The center O(x,y) of the given circle is the intersection of the perpendicular bisectors of the chords AB and CD. The equations of these perpendiculars are:
x=1/2(a+b) and y=1/2(c+d) respectively.
## Answer
(2a+b;2c+d)
Source: NuminaMath-1.5,
licensed Apache-2.0.
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