Olympiad Maths Prep

Track / Stage 4 / 112 of 340 #372 of 2000

Problem 372

AMC 12 late, AIME early
Combinatorics Difficulty 4.8 Find the answer

15. (1999 American High School Mathematics Examination) Given six points on a circle, any combination of four chords can form a convex quadrilateral. The probability that they form a convex quadrilateral is ( ).
A. 115\frac{1}{15}
B. 191\frac{1}{91}
C. 1273\frac{1}{273}
D. 1455\frac{1}{455}
E. 11365\frac{1}{1365}

Official solution

15. B. Reason: The total number of chords that can be connected by the six given points is C62=15C_{6}^{2}=15; the number of ways to choose four chords from these is C154C_{15}^{4}. According to the problem, the number of convex quadrilaterals that can be formed by the chords connecting the six points is C64C_{6}^{4}, thus the required probability is
P=C6C15=191. P=\frac{C_{6}}{C_{15}}=\frac{1}{91} .

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