Olympiad Maths Prep

Track / Stage 4 / 190 of 340 #450 of 2000

Problem 450

AMC 12 late, AIME early
Algebra Difficulty 4.8 Find the answer

4. Solve the equation (log4(x+1)+log42(x+1)+1)(log4(3x+5)+log42(3x+5)+1)=1\left(\log _{4}(x+1)+\sqrt{\log _{4}^{2}(x+1)+1}\right)\left(\log _{4}(3 x+5)+\sqrt{\log _{4}^{2}(3 x+5)+1}\right)=1.

Official solution

Answer: x=23x=-\frac{2}{3}.

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.