Given a circle and the segment . The lengths of the tangent segments drawn from and to are and , respectively. Is it true that if and only if the segment has no common points with ?
Problem 1081
Official solution
The task only makes sense if neither nor falls inside the circle. If neither nor is on the circumference of the circle, then the statement is true; otherwise, it is not. If, for instance, is on the circumference and is outside the circle, then , so , but the segment has a common point with , so in this case, the statement is not true (Figure 1).
If both and are outside the circle, we need to examine the following three cases:
(i) is outside ,
(ii) touches at a point ,
(iii) intersects .
The statement of the problem is that in case (i), , while in the other two cases, . In all three cases, it is true that the two tangent segments drawn from and to are of equal length, so it is always sufficient to examine the tangent segment that is more favorably positioned for us.
In case (i), we can assume that one of the two tangent lines separates and (i.e., the circle and the segment are on different sides of the tangent line), while the other does not. In our diagram, the tangent from is the separating one. Then the intersection point of the two tangent lines will be an internal point of the tangent segment from , but not of the tangent segment from . The points will be arranged as shown in Figure 2. Using the notation from the diagram:
However, by the triangle inequality, , so the statement of the problem is true in this case.
In case (ii) (Figure 3), , so the statement is clearly true in this case.
In case (iii), we draw the tangents whose points of tangency are separated from the center of the circle by (Figure 4). Let the intersection points of the radii and with be and , respectively. Then the points are arranged in this order, and and may coincide if is on , so .
This proves that the statement of the problem is true precisely when both and are outside the circle.
Based on the work of Gábor Nyul (Debrecen, Fazekas M. Gymnasium, 1st year)
!
!