Olympiad Maths Prep

Track / Stage 4 / 158 of 340 #418 of 2000

Problem 418

AMC 12 late, AIME early
Algebra Difficulty 4.8 Find the answer

23. For any real numbers aa, bb, cc, define an operation ※ with the following properties:
(1) a(bc)=(ab)ca ※(b ※ c)=(a ※ b) \cdot c,
(2) aa=1a ※ a=1,

where “\cdot” denotes multiplication.
If the solution to the equation 2016×(6x)=1002016 \times(6 ※ x)=100 is x=pq(p,qx=\frac{p}{q}(p, q are positive integers, (p,q)=1)(p, q)=1), then the value of p+qp+q is ()(\quad).
(A) 109
(B) 201
(C) 301
(D) 3049
(E) 33601

Official solution

23. A.
 Given 2016(6x)=(20166)x(20166)6=600x2016(66)=600x. \begin{array}{l} \text { Given } 2016 ※(6 ※ x)=(2016 ※ 6) \cdot x \\ \Rightarrow(2016 ※ 6) \cdot 6=\frac{600}{x} \\ \Rightarrow 2016 ※(6 ※ 6)=\frac{600}{x} . \end{array}

Since aa=1a ※ a=1, we have,
66=20162016=1. Therefore 2016(20162016)=600x(20162016)2016=600x12016=600xx=2584p+q=25+84=109. \begin{array}{l} 6 ※ 6=2016 ※ 2016=1 . \\ \text { Therefore } 2016 ※(2016 ※ 2016)=\frac{600}{x} \\ \Rightarrow(2016 ※ 2016) \cdot 2016=\frac{600}{x} \\ \Rightarrow 1 \cdot 2016=\frac{600}{x} \Rightarrow x=\frac{25}{84} \\ \Rightarrow p+q=25+84=109 . \end{array}

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.