23. For any real numbers a, b, c, define an operation ※ with the following properties: (1) a※(b※c)=(a※b)⋅c, (2) a※a=1,
where “⋅” denotes multiplication. If the solution to the equation 2016×(6※x)=100 is x=qp(p,q are positive integers, (p,q)=1), then the value of p+q is (). (A) 109 (B) 201 (C) 301 (D) 3049 (E) 33601
Official solution
23. A. Given 2016※(6※x)=(2016※6)⋅x⇒(2016※6)⋅6=x600⇒2016※(6※6)=x600.
Since a※a=1, we have, 6※6=2016※2016=1. Therefore 2016※(2016※2016)=x600⇒(2016※2016)⋅2016=x600⇒1⋅2016=x600⇒x=8425⇒p+q=25+84=109.
Source: NuminaMath-1.5,
licensed Apache-2.0.
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