5. Let vectors a and b satisfy ∣a∣=1,∣b∣=2, and the angle between a and b is 60∘. If the angle between the vectors 7a+2tb and ta+b is obtuse, then the range of the real number t is
Official solution
5. −7<t<−21, and t=−214.
From (7a+2tb)⋅(ta+b)<0, we get −7<t<−21. Moreover, the angle between 7a+2tb and ta+b must not be a straight angle, hence, t=−214.
Source: NuminaMath-1.5,
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