10. 112 .
From the problem, we know
Sn+1−Sn=∣n∣+2∣n−1∣+⋯+10∣n−9∣−[∣n−1∣+2∣n−2∣+⋯+10∣n−10∣]=∣n∣+∣n−1∣+⋯+∣n−9∣−10∣n−10∣.
When n⩾10, Sn+1−Sn>0, thus, Sn is monotonically increasing; □
When n=0, S1−S0>0;
When n=6, S7−S6<0.
Therefore, Sn is monotonically decreasing in the interval [1,7] and monotonically increasing in the interval [7,+∞).
Hence, the minimum value of Sn is S7=112.