4. (20 points) A bullet with a mass of m=10 g, flying horizontally at a speed of v1=400m/s, penetrates a massive board and exits with a speed of v2=100m/s. Find the magnitude of the work done on the bullet by the resistance force of the board.
Official solution
Answer: 750 J
Solution. From the law of conservation of energy, it follows that
A=2mv12−2mv22=20.01⋅4002−20.01⋅1002=750 J.
Source: NuminaMath-1.5,
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