Olympiad Maths Prep

Track / Stage 4 / 138 of 340 #398 of 2000

Problem 398

AMC 12 late, AIME early
Algebra Difficulty 4.8 Find the answer

1.69 Calculate:
(4)55(5)25+(43)44(32) \sqrt[5]{(-4)^{5}}-(-5)^{2}-5+\sqrt[4]{(-43)^{4}}-\left(-3^{2}\right)

The result is
(A) 0.
(B) -68.
(C) 18.
(D) -86.
(China Beijing Junior High School Mathematics Competition, 1982)

Official solution

 [Solution] (4)55(5)25+(43)44(32)=(4)255+43+9=18. \text { [Solution] } \begin{aligned} & \sqrt[5]{(-4)^{5}}-(-5)^{2}-5+\sqrt[4]{(-43)^{4}}-\left(-3^{2}\right) \\ = & (-4)-25-5+43+9 \\ = & 18 . \end{aligned}

Therefore, the correct choice is (C)(C).

Source: NuminaMath-1.5, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.