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Problem 398
AMC 12 late, AIME early Algebra Difficulty 4.8 Find the answer
1.69 Calculate:
5(−4)5−(−5)2−5+4(−43)4−(−32)
The result is
(A) 0.
(B) -68.
(C) 18.
(D) -86.
(China Beijing Junior High School Mathematics Competition, 1982)
Official solution
[Solution] ==5(−4)5−(−5)2−5+4(−43)4−(−32)(−4)−25−5+43+918.
Therefore, the correct choice is (C).
Source: NuminaMath-1.5,
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