47. Let a1,a2,⋯,an;b1,b2,⋯,bn be two sequences of positive numbers. Prove: (∑i=jaibj)2⩾(∑i=jaiaj)(∑i=jbibj)⋅(1998 Yugoslav Mathematical Olympiad problem)
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Official solution
47. Let A=∑i=1nai,B=∑i=1nbi, the problem is equivalent to proving: (AB−∑i=1naibi)2⩾(A2−∑i=1nai2)(B2−∑i=1nbi2)
Construct a quadratic function: f(x)=(A2−∑i=1nai2)x2+2(AB−∑i=1naibi)x+(B2−∑i=1nbi2). We need to prove that its discriminant Δ⩾0, now we just need to verify that there exists a real number x0 such that f(x0)⩽0, take x0=−AB,f(−AB)⩽0⇔B2i=1∑nai2−2ABi=1∑naibi+A2i=1∑nbi2⩾0
To prove (1), we just need to prove that its discriminant Δ1⩽0, which is obtained by the Cauchy-Schwarz inequality (∑i=1naibi)2⩽∑i=1nai2∑i=1nbi2.
Source: NuminaMath-1.5,
licensed Apache-2.0.
Statement and solution reproduced as published; topic, difficulty and ordering added
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