A line through the origin passes through the curve whose equation is 5y=2x2−9x+10 at two points whose x−coordinates add up to 77. Find the slope of the line.
Official solution
1. Let the equation of the line through the origin be y=kx, where k is the slope of the line. 2. Substitute y=kx into the given equation of the parabola 5y=2x2−9x+10: 5(kx)=2x2−9x+10 Simplify this to: 5kx=2x2−9x+10 3. Rearrange the equation to form a standard quadratic equation: 2x2−(9+5k)x+10=0 4. By Vieta's formulas, the sum of the roots of the quadratic equation ax2+bx+c=0 is given by −ab. Here, a=2 and b=−(9+5k), so the sum of the roots is: 29+5k 5. We are given that the sum of the x-coordinates of the points where the line intersects the parabola is 77. Therefore, we set up the equation: 29+5k=77 6. Solve for k: 9+5k=154 5k=145 k=29
The final answer is 29.
Source: NuminaMath-1.5,
licensed Apache-2.0.
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