Olympiad Maths Prep

Track / Stage 8 / 120 of 180 #1820 of 2000

Problem 1820

IMO Shortlist mid-range; USAMO P2/P5
Combinatorics Difficulty 8.6 Find the answer imo

Let n2n \ge 2 be an integer. Consider an n×nn \times n chessboard consisting of n2n^2 unit squares. A configuration of nn rooks on this board is [i]peaceful[/i] if every row and every column contains exactly one rook. Find the greatest positive integer kk such that, for each peaceful configuration of nn rooks, there is a k×kk \times k square which does not contain a rook on any of its k2k^2 unit squares.

Official solution

Let n2 n \geq 2 be an integer, and consider an n×n n \times n chessboard. We place n n rooks on this board such that each row and each column contains exactly one rook. This is defined as a peaceful configuration of rooks. The objective is to find the greatest positive integer k k such that, in every possible peaceful configuration of n n rooks, there exists a k×k k \times k sub-square on the chessboard that is completely empty of any rooks.

### Step-by-step Solution

1. Understanding the Problem:
- In a peaceful configuration, since there is exactly one rook per row and one per column, it ensures all n n rooks are placed in unique row-column intersections across the n×n n \times n board.

2. Identifying Empty Squares:
- We need to ensure every configuration allows for a square sub-board of size k×k k \times k which is void of rooks.

3. **Calculation of Maximum k k :**
- If we realize a peaceful configuration where rooks are distributed such that they occupy maximum area of the available board, each row and column combination will optimally cover the board minimally.
- The goal is maximizing k k , ensuring the largest empty k×k k \times k square still forms on any part of the board in spite of any rook configuration.

4. Using Combinatorial and Geometric Argument:
- Let’s consider placing n1 n-1 rooks. In this optimal configuration, potentially every position leading to n1 n-1 coverages leaves a square potentially of size up to
n1×n1\sqrt{n - 1} \times \sqrt{n - 1} that is free.
- For all n n positions to be filled, this sub-square will obviously be smaller in the maximal empty form.

5. Conclusion:
- Upon deriving these options and observance that the largest k×k k \times k square exists, due to nk\lceil\frac{n}{k}\rceil fraction of remaining free subset, we form:
- The greatest k k ensuring a k×k k \times k rupe-free square is presented by the integer part:
k=n1. k = \left\lfloor \sqrt{n - 1} \right\rfloor.

Thus, the greatest positive integer k k such that for any peaceful configuration, there exists a k×k k \times k sub-square devoid of rooks, is:
n1. \boxed{\left\lfloor \sqrt{n - 1} \right\rfloor}.

Source: Omni-MATH, licensed Apache-2.0. Statement and solution reproduced as published; topic, difficulty and ordering added by this site.