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CEMC Fermat, 2024

Algebra Difficulty 2.5 Junior Find the answer Canada

For some integers mm and
nn, the expression (x+m)(x+n)(x+m)(x+n) is equal to a quadratic
expression in xx with a constant
term of −12-12. Which of the following
cannot be a value of mm?

Pick one

Solution

Expanding, (x+m)(x+n)=x2+nx+mx+mn=x2+(m+n)x+mn(x+m)(x+n) = x^2 + nx + mx + mn = x^2 + (m+n)x + mn.

The constant term of this quadratic expression is mnmn, and so mn=−12mn = -12.

Since mm and nn are integers, they are each divisors of
−12-12 and thus of 1212.

Of the given possibilities, only 55 is not a divisor of 1212, and so mm cannot equal 55.

We can check that each of the other four choices is a possible value of
mm.

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.