Maths Olympiad Prep

Library / /197 of 472

, 1998

Number theory Difficulty 2.0 Junior Find the answer Canada

The number of solutions (x,y)(x, y) of the equation 3x+y=1003x + y = 100, where xx and yy are positive integers, is

(A) 3333 (B) 3535 (C) 100100 (D) 101101 (E) 9797

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.