Maths Olympiad Prep

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, 2003

Algebra Difficulty 3.0 AMC 10/12 Prove it Canada

Solve the system of equations:
log10(x3)+log10(y2)=11\log_{10}(x^3)+\log_{10}(y^2)=11
log10(x2)log10(y3)=3\log_{10}(x^2)-\log_{10}(y^3)=3

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.