Library / /10 of 413

, 1999

Algebra Difficulty 1.0 Junior Find the answer Canada

$\frac{1}{2} + \frac{1}{3}$ is equal to

(A) $\frac{2}{5}$ (B) $\frac{1}{6}$ (C) $\frac{1}{5}$ (D) $\frac{3}{2}$ (E) $\frac{5}{6}$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.