Maths Olympiad Prep

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, 2000

Algebra Difficulty 1.0 Junior Find the answer Canada

If 23\dfrac{2}{3}, 2330\dfrac{23}{30}, 910\dfrac{9}{10}, 1115\dfrac{11}{15}, and 45\dfrac{4}{5} are written from smallest to largest then the middle fraction will be

(A) 2330\dfrac{23}{30} (B) 45\dfrac{4}{5} (C) 23\dfrac{2}{3} (D) 910\dfrac{9}{10} (E) 1115\dfrac{11}{15}

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.