Library / /18 of 475

, 1998

Algebra Difficulty 1.0 Junior Find the answer Canada

If $x + y + z = 25$ and $y + z = 14$ , then $x$ is

(A) $8$ (B) $11$ (C) $6$ (D) $-6$ (E) $31$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.