CEMC Fermat, 2012

Algebra Difficulty 1.2 Junior Find the answer Canada

John ate a total of 120 peanuts over four consecutive nights. Each night he ate 6 more peanuts than the night before. How many peanuts did he eat on the fourth night?

Pick one

Solution

Suppose that John ate $x$ peanuts on the fourth night.

Since he ate 6 more peanuts each night than on the previous night, then he ate $x-6$ peanuts on the third night, $(x-6)-6=x-12$ peanuts on the second night, and $(x-12)-6=x-18$ peanuts on the first night.

Since John ate $120$ peanuts in total, then $x+(x-6)+(x-12)+(x-18)=120$ , and so $4x - 36 = 120$ or $4x = 156$ or $x = 39$ .

Therefore, John ate 39 peanuts on the fourth night.

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