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Algebra Difficulty 1.1 Junior Find the answer Canada

The value of $\dfrac{101^2-101}{100}$ is

Pick one

Solution

Solution 1:

Factoring the numerator and simplifying, we get $\dfrac{101^2-101}{100}=\dfrac{101(101-1)}{100}=\dfrac{101(100)}{100}=101$ .

Solution 2:

Evaluating, we get $\dfrac{101^2-101}{100}=\dfrac{10\,201-101}{100}=\dfrac{10\,100}{100}=101$ .

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.