Library / /23 of 475

, 2008

Algebra Difficulty 1.0 Junior Find the answer Canada

$2^3\times 2^2\times 3^3\times 3^2$ is equal to

(A) $6^5$ (B) $6^6$ (C) $6^{10}$ (D) $36^{10}$ (E) $36^{36}$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.