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, 2008

Number theory Difficulty 2.0 Junior Find the answer Canada

The sum of all of the digits of the integers from $98$ to $101$ is $9+8+9+9+1+0+0+1+0+1=38$ The sum of all of the digits of the integers from $1$ to $2008$ is

(A) $30\,054$ (B) $27\,018$ (C) $28\,036$ (D) $30\,036$ (E) $28\,054$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.