Library / /206 of 472

, 2002

Number theory Difficulty 2.0 Junior Find the answer Canada

If $2^a 3^b = 8\left(6^{10}\right)$ , where $a$ and $b$ are integers, then $b-a$ equals

(A) $0$ (B) $23$ (C) $-13$ (D) $-7$ (E) $-3$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.