Solution 1:
The volume of Cylinder A is π×22×8=32π, and so the
volume of water in Cylinder A is 43×32π=24π.
If all of the water from Cylinder A is poured into Cylinder B, the
volume of water in Cylinder B is 24π.
The volume of Cylinder B is π×82×2=128π, and so the
fraction of Cylinder B that is full of water is 128π24π=163.
Solution 2:
As in Solution 1, the volume of water in Cylinder B would be 24π.
Suppose that the height of the water in Cylinder B is h.
Then, π×82×h=24π
or h=64π24π=83.
Since the height of Cylinder B is 2
and the height of the water is 83, then the fraction of Cylinder B
that is full of water is 23/8=163.