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Algebra Difficulty 2.7 Junior Find the answer Canada

A bin contains 10 kg of peanuts. 2 kg of peanuts are removed and 2 kg of raisins are added and thoroughly mixed in. Then 2 kg of this mixture are removed and 2 kg of raisins are added and thoroughly mixed in again. What is the ratio of the mass of peanuts to the mass of raisins in the final mixture?

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Solution

When 2 kg of the 10 kg of peanuts are removed, there are 8 kg of peanuts remaining.

Since 2 kg of raisins are added, then there are 2 kg of raisins in the bin.

The peanuts and raisins are thoroughly mixed.

Since 2 kg of this mixture is removed and this is one-fifth of the total mass, then one-fifth of the mass of peanuts (or 85\frac{8}{5} kg) is removed and one-fifth of the mass of raisins (or 25\frac{2}{5} kg) is removed.

This leaves 885=3258 - \frac{8}{5} = \frac{32}{5} kg of peanuts, and 225=852-\frac{2}{5} = \frac{8}{5} kg of raisins.

When 2 kg of raisins are added, the mass of raisins becomes 85+2=185\frac{8}{5}+2=\frac{18}{5} kg.

There are 325\frac{32}{5} kg of peanuts and 185\frac{18}{5} kg of raisins in the bin.

Therefore, the ratio of the masses is 325:185=32:18=16:9\frac{32}{5}:\frac{18}{5} = 32:18=16:9.

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.