CEMC Fermat, 2009

Combinatorics Difficulty 2.0 Junior Find the answer Canada

Six dice are stacked on the floor as shown. On each die, the 1 is opposite the 6, the 2 is opposite the 5, and the 3 is opposite the 4. What is the maximum possible sum of numbers on the 21 visible faces?

(A) $69$ (B) $88$ (C) $89$ (D) $91$ (E) $96$

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