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, 2021

Algebra Difficulty 1.1 Junior Find the answer Canada

When $x=2021$ , the value of $\dfrac{4x}{x+2x}$ is

$\dfrac{3}{4}$
$\dfrac{4}{3}$
$2021$
$2$
$6$

Your answer

A number or a short expression. Fractions can be typed as 3/2, and spacing doesn't matter.

Solution

When $x \neq 0$ , we obtain $\dfrac{4x}{x+2x} = \dfrac{4x}{3x} = \dfrac{4}{3}$ .
Thus, when $x = 2021$ , we have $\dfrac{4x}{x+2x} = \dfrac{4}{3}$ .
Alternatively, we could substitute $x = 2021$ to obtain $\dfrac{4x}{x+2x} = \dfrac{8084}{2021+4042} = \dfrac{8084}{6063} = \dfrac{4}{3}$ .

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project.