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Number theory Difficulty 3.0 AMC 10/12 Find the answer Canada

Positive integers $a$ and $b$ satisfy $ab = 2010$ . If $a > b$ , the smallest possible value of $a - b$ is

(A) $37$ (B) $119$ (C) $191$ (D) $1$ (E) $397$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.