Library / /64 of 475

, 2002

Number theory Difficulty 1.0 Junior Find the answer Canada

When the product $\left(5^3\right)\left(7^{52}\right)$ is expanded, the units digit (that is, the last digit) is

(A) $5$ (B) $3$ (C) $9$ (D) $7$ (E) $0$

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Source: CEMC, University of Waterloo, licensed CC-BY-NC-4.0. Statement reproduced verbatim; metadata (topic, difficulty) added by this project. Solutions are the publisher's, linked not copied.